First page Back Continue Last page Overview Image
- PHY102 Physics II © Dr.Cem Özdoğan
- The volume flow rate (volume per unit time) at which air flows through the loop is = (v cos )A.
- Fig. 23-2 (a) A uniform airstream of velocity v is perpendicular to the plane of a square loop of area A.
- (b) The component of v perpendicular to the plane of the loop is v cos, where , is the angle between v
- and a normal to the plane.
- (c) The area vector A is perpendicular to the plane of the loop and has a magnitude equal to the area of the loop; that is A. Here, A makes an angle , with v.
- (d) The velocity field intercepted by the area of the loop.
- This equation can also be interpreted as the flux of the velocity field through the loop. With this interpretation, flux is no longer means the actual flow of something through an area - rather it means the product of an area and the field across that area.
- This rate of flow through an area is an example of a flux- a volume flux in this situation- which can be rewritten in terms of vectors as